Given that the random variable X is normally distributed with a mean of 80 and a standard deviation of 10, P(85 X 90) is a. 0.3413 b. 0.1498 c. 0.5328 d. 0.1915

Respuesta :

Answer:

The answer is b.) 0.1498

Step-by-step explanation:

The normal distribution of a random variable, x, is said to have a mean, [tex]\mu[/tex] = 80 and a standard deviation, [tex]\sigma[/tex]  = 10.

We have to find the probability of P(85 < x < 90) .

We first find the Z values which represent the x variable by using the formula Z = [tex]\frac{x - \mu}{\sigma}[/tex].

Thus   we can write

 P( 85 < x < 90)

= P( [tex]\frac{(85 - 80)}{10} < Z < \frac{(90 - 80)}{10}[/tex])

= P(0.5 < Z < 1)

= P(Z < 1)  - P(Z < 0.5).

When we are asked to probabilities between two values we can separate them into two probabilities and find their difference to give the answer as shown above.

From the Z - tables we can calculate P(Z < 0.5) = 0.6915 and P(Z < 1) = 0.8413

Therefore   P( 85 < x < 90) = 0.8413 - 0.6915 = 0.1498.

The answer is b.) 0.1498