miyapooh6049 miyapooh6049

25-02-2020
Chemistry

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The equilibrium constant for reaction (1) is K. The equilibrium constant for reaction (2) is ______. (1) SO2(g) + ½ O2(g) ⇌ SO3(g) (2) 2 SO3(g) ⇌ 2 SO2(g) + O2(g)

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Jerryojabo1 Jerryojabo1

25-02-2020

Answer: 1/k

Explanation: the reaction will be express as [S02]2 . [02]/[S03]2

This is the reversible reaction of reaction (1) whose equilibrium constant is k, hence k2=1/k1.

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