Answer and Step-by-step explanation:
[tex]We~ need ~to ~find ~the~ HCF~ of ~1624, 522 ~and~ 1276~so~in~order~to~find~this[/tex] [tex]we~will~have~to~use~prime~factorization.[/tex]
→ Prime factorization of 1624 is :
= 2 × 2 × 2 × 7 × 29
→ Prime factorisation of 522 is :
= 2 × 3 × 3 × 29
→ Prime factorisation of 1276 is :
= 2 × 2 × 29 × 11
→ [tex]HCF~of~1624 , 522 , 1276~is:[/tex] [tex]=2[/tex]× [tex]29=58[/tex]
