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Two samples of calcium fluoride are decomposed into their constituent elements. The first sample produced 0.154 g of calcium and 0.146 g of fluorine. If the second sample produced 294 mg of fluorine, how many g of calcium were formed?

Respuesta :

Answer : The mass of calcium in sample B is, 0.310 grams.

Explanation :

Law of definite proportion : It is defined as a given compound always contains exactly the same proportion of elements by weight.

Now we have to calculate the mass of calcium in sample B.

As, first sample of 0.146 g of fluorine = second sample of 0.294 g of fluorine

So, first sample of 0.154 g of calcium = second sample of [tex]\frac{0.154}{0.146}\times 0.294=0.310g[/tex] of calcium

Therefore, the mass of calcium in sample B is, 0.310 grams.

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