A box of candy contains two types of chocolates. One type is made with nuts, and the other type is nut free. The box contains 6 times more candies with nuts than candies without nuts. Johnny pulls a candy out of the box at random. What is the probability that Johnny pulled out a candy without nuts?

Respuesta :

Answer: [tex]\dfrac{1}{7}.[/tex]

Step-by-step explanation:

Let [tex]x[/tex] be the number of candies without nuts.

Then, the number of candies with nuts = [tex]6x[/tex]

Total number of candies in box = [tex]6x+x=7x[/tex]

Now , the probability that Johnny pulled out a candy without nuts will be :

[tex]\dfrac{x}{7x}=\dfrac{1}{7}\ \ \ [\text{cancel x from both numerator and denominator.}][/tex]

Hence, the probability that Johnny pulled out a candy without nuts is [tex]\dfrac{1}{7}.[/tex]

Answer:

1/4

Step-by-step explanation:

What is the probability that Johnny pulled out a candy without nuts?

1/4 is the probability he will get candy without nuts.