Respuesta :
Answer:
distance of the second dark fringe from the center of the bright fringe is 0.92 cm
Explanation:
given data
wavelength = 610 nm = 610 × [tex]10^{-9}[/tex] m
slit of width = 0.20 mm = 0.20 × [tex]10^{-3}[/tex] m
distance between screen and slit = 1.5 m
solution
we apply here formula for second minima that is
L = [tex]\frac{n \lambda D}{d}[/tex] ...................1
and here for second minima n is 2
put here value we get
L = [tex]\frac{2*610*10^{-9}*1.5}{0.20*10^{-3}}[/tex]
L = 0.915 × [tex]10^{-2}[/tex] m
so distance of the second dark fringe from the center of the bright fringe is 0.92 cm
The distance of the second dark fringe from the center of the bright fringe is 0.92 cm
Calculation of the distance:
Since Light of wavelength 610 nm is incident on a slit of width 0.20 mm, a diffraction pattern is produced on a screen that is 1.5 m from the slit.
So, the distance is
[tex]= 2 \times 610 \times 10^{-9} \times 1.5 \div 0.20 \times 10^{-3}\\\\= 0.915 \times 10^{-2}[/tex]
= 0.92 cm
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