Respuesta :
Answer:169.87g|mol
Explanation: AgNO3
Ag =107.87 N=14.01 O=16.00
107.87+14.01+16.0
=169.87g|mol
The mass of silver nitrate is 731 grams.
Number of moles:
It is defined as given mass over molar mass.
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given:
Moles of silver nitrate= 4.3 moles
Molar mass of silver nitrate = 170g/mol
To find:
Mass of silver nitrate= ?
Substituting the values in the above formula:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\\text{Mass}= \text{Number of moles}*\text{Molar mass}\\\\\text{Mass}=4.3moles*170g/mol\\\\\text{Mass}=731g[/tex]
So, mass of silver nitrate is 731 grams.
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