Respuesta :

Answer:169.87g|mol

Explanation: AgNO3

Ag =107.87 N=14.01 O=16.00

107.87+14.01+16.0

=169.87g|mol

The mass of silver nitrate is 731 grams.

Number of moles:

It is defined as given mass over molar mass.

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Given:

Moles of silver nitrate= 4.3 moles

Molar mass of silver nitrate = 170g/mol

To find:

Mass of silver nitrate= ?

Substituting the values in the above formula:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\\\\\text{Mass}= \text{Number of moles}*\text{Molar mass}\\\\\text{Mass}=4.3moles*170g/mol\\\\\text{Mass}=731g[/tex]

So, mass of silver nitrate is 731 grams.

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