Answer:
a) 1201.6 grams of HNO3 is produced
b) The minimum amount of O2 is 915.2 grams
Explanation:
Step 1: Data given
Mass of N2 = 400 grams
Molar mass N2 = 28.0 g/mol
Step 2: The balanced equation
N2 (g) + 2O2 (g) → 2 NO2 (g)
3NO2 (g) + H2O (g) → 2HNO3 (aq) + NO (g)
Step 3: Calculate moles N2
Moles N2 = mass N2 / molar mass N2
Moles N2 = 400 grams / 28.0 g/mol
Moles N2 = 14.3 moles
Step 4: Calculate moles O2
For 1 mol N2 we need 2 moles O2 to produce 2 moles NO2
For 14.3 moles N2 we need 28.6 moles O2 to produce 28.6 moles NO2
Step 5: Calculate mass O2
Mass O2 = moles O2 * molar mass O2
Mass O2 = 28.6 moles * 32.0 g/mol
Mass O2 = 915.2 grams
Step 6: Calculate moles NO2
For 14.3 moles N2 we need 28.6 moles O2 to produce 28.6 moles NO2
Step 7: Calculate moles HNO3
For 3 moles NO2 we need 1 moles H2O to produce 2 moles HNO3 and 1 mol NO
For 28.6 moles NO2 we need 2/3 * 28.6 = 19.07 moles HNO3
Step 8: Calculate mass HNO3
Mass HNO3 = moles HNO3 * molar mass HNO3
Mass HNO3 = 19.07 g/mol * 63.01 g/mol
Mass HNO3 = 1201.6 grams
1201.6 grams of HNO3 is produced
