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A man consumes 2055 kcal of food in one day, converting most of it to body temperature. If he loses half this energy by evaporating water (through breathing and sweating), how many kilograms of water evaporate?

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Answer:

3.81kg

Explanation:

Given that heat lost by man Q= 2055kCal

Latent heat of water L = 540KCal/Kg

Mass of water evaporated = M

Using

Q= ML

2055= M * 540

M= 2055/540

M= 3.81kg

Answer:

1.903 kg.

Explanation:

Energy obtained from the food, Q= 2055kCal

Half of the energy lost to evaporating water = 2055/2

= 1027.5 kCal

Latent heat of water, L = 540 kCal/kg

Q= m × L

m = 1027.5/540

= 1.903 kg.