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What mass of Na2SO4 is needed to make 2.0 L of 3.0 M solution (Na = 23 g; S = 32 g; O = 16 g)

PLEASE help my teacher never teaches :( I will mark brainiest

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limenade0

Answer: 710.5g

Explanation:

Moles of Na2SO4 = conc. x volume(dm3)

= 2 x (2500cm3/1000)

= 5 mol

Mass of Na2SO4 = moles x molar mass

= 5 x ((23 x 2) + 32.1 + (16 x 4))

= 710.5g

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