Answer:
−2399.33 kJ
Explanation:
If NH₄NO₃ reacts with fuel oil to give a ΔH of -7198 for every 3 moles of NH₄NO₃
What is the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction
∴ For every 1 mole, we will have [tex]\frac{1}{3}[/tex] of the total enthaply of the 3 moles
so, to determine the 1 mole; we have:
[tex]\frac{1}{3}*(-7198kJ)[/tex]
= −2399.33 kJ
∴ the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction = −2399.33 kJ
