Answer:
[tex]53.13^{0}[/tex]
Step-by-step explanation:
Consider vector A as shown in the figure given. The x- and y-component of vectors are given as Ax and Ay.
The angle of the vector with positive x-axis is given by,
∅ =[tex]Tan^{-1}[/tex] ([tex]\frac{Ay}{Ax}[/tex])
= [tex]Tan^{-1}[/tex] ([tex]\frac{3}{4}[/tex])
= [tex]36.86^{0}[/tex]
Where: Ax = x-component of the vector ann Ay=x-component of the vector
Thus, the angle of vector:
α = 90-∅
= [tex]53.13^{0}[/tex]
The angle that this vector makes with the positive y-axis is 53.13°.
A vector is said to be in a standard position if its initial point is the origin (0, 0).
If the two vectors are assumed as a and b then the dot created is defined as a .b.
Given
A vector is located in the x-y plane.
The x and y components of this vector are 4.00 m and 3.00 m, respectively.
Let the angle that this vector makes with the positive y-axis be α.
The angle of the vector with the positive x-axis is given by;
[tex]\rm tan\theta=\dfrac{AY}{AX}[/tex]
Substitute all the values in the formula;
[tex]\rm tan\theta=\dfrac{AY}{AX}\\\\\rm tan\theta=\dfrac{3}{4}\\\\\theta=tan{-1}\dfrac{3}{4}\\\\\theta=36.86 \ degrees[/tex]
Therefore,
the angle that this vector makes with the positive y-axis is;
α = 90 - 36.86 =53.13°
Hence, the angle that this vector makes with the positive y-axis is 53.13°.
To know more about vectors click the link given below.
https://brainly.com/question/14285007
