Answer: The value of k is 0.09.
Step-by-step explanation:
Since we have given that
[tex]P(t)=P(0)e^{kt}[/tex]
Here, k is the rate ,
t is the time,
In 2004, the whooping cranes tallied 213 birds,
So, P(t)=213
It is 19 greater than 2003,
So, P(0)=213-19=194
So, substitute all the values in given expression:
[tex]213=194e^{k.1}\\\\\dfrac{213}{194}=e^k\\\\1.098=e^k\\\\\text{Taking log on both the side}\\\\\ln 1.098=k\\\\k=0.09[/tex]
Hence, the value of k is 0.09.