Answer:
a.[tex]6.76 m/s^2[/tex]
b.30.4 N
Explanation:
We are given that
Mass of block=m=1.1 kg
Mass of cart=M=3.4 kg
Total mass=m+M=1.1+3.4=4.5 Kg
[tex]\mu=0.69[/tex]
1.We have to find the maximum acceleration such that block does not slide on the cart.
Normal force=[tex]\mu mg[/tex]
[tex]\mu mg=ma[/tex]
[tex]a=\mu g[/tex]
Substitute the values
[tex]a=0.69\times 9.8=6.76 m/s^2[/tex]
Using [tex]g=9.8m/s^2[/tex]
Hence, the maximum acceleration such that block does not slide on the cart=[tex]6.76 m/s^2[/tex]
b.[tex]F=ma_{max}[/tex]
Using the formula
[tex]F=4.5\times (6.76)=30.4 N[/tex]
Hence, the magnitude of the force on the cart required to provide the maximum acceleration=30.4 N
