contestada

The function​ A(s) given by ​A(s)equals0.328splus50 can be used to estimate the average age of employees of a company in the years 1981 to 2009. Let​ A(s) be the average age of an​ employee, and s be the number of years since​ 1981; that​ is, sequals0 for 1981 and sequals9 for 1990. What was the average age of the employees in 2003 and in​ 2009?

Respuesta :

Answer:

  • Average age of the employees in 2003 = 57.216
  • Average age of the employees in​ 2009 = 59.184

Step-by-step explanation:

We are given the function​ A(s) as;

           A(s) = 0.328*s + 50   where s = number of years since​ 1981; that​ is,

                                                   s = 0 for 1981 and s = 9 for 1990

A(s) = the average age of an​ employee

  • Now, the average age of the​ employees in 2003, A(22) = 0.328*22 + 50

        Here s = 22 because 2003 - 1981 = 22 years

Therefore, average age of the​ employees in 2003 = 7.216 + 50 = 57.216 .

  • Average age of the employees in​ 2009, A(28) = 0.328*28 + 50

        Here, s = 28 because 2009 - 1981 = 28 years

Therefore, average age of the​ employees in 2009 = 9.184 + 50 = 59.184 .