Respuesta :
Answer: The work done for the given process is -6813.44 J
Explanation:
To calculate the amount of work done for an isothermal process is given by the equation:
[tex]W=-P\Delta V=-P(V_2-V_1)[/tex]
W = amount of work done = ?
P = pressure = 1.9 atm
[tex]V_1[/tex] = initial volume = 113.1 L
[tex]V_2[/tex] = final volume = 148.5 L
Putting values in above equation, we get:
[tex]W=-1.9atm\times (148.5-113.1)L=-67.26L.atm[/tex]
To convert this into joules, we use the conversion factor:
[tex]1L.atm=101.33J[/tex]
So, [tex]-67.26L.atm=-67.26\times 101.3=-6813.44J[/tex]
The negative sign indicates the system is doing work.
Hence, the work done for the given process is -6813.44 J
The work done for the given process is -6813.44 J
Calculation of work done:
To calculate the amount of work done for an isothermal process is given by the equation:
[tex]W=-P\triangle V=-P(V_2-V_1)[/tex]
where,
W = amount of work done = ?
P = pressure = 1.9 atm
V₁ = initial volume = 113.1 L
V₂ = final volume = 148.5 L
On substituting the values:
[tex]W=-1.9atm*(148.5-113.1)L\\\\W=62.26Latm[/tex]
The negative sign shows the system is doing work.
Hence, the work done for the given process is -6813.44 J.
Find more information about Work done here:
brainly.com/question/25573309
