Answer:
The answer to your question is 303 in
Step-by-step explanation:
Data
Painting 1212 in x 1414 in
Perimeter painting + frame = 7676
width of the frame = ?
Process
1.- Calculate the perimeter of the painting
Perimeter = 2 length + 2 width
Perimeter = 2(1212) + 2(1414)
Perimeter = 2424 + 2828
Perimeter = 5252 in
2.- Subtract both perimeters
7676 - 5252 = 2424 in
3.- Divide the result by 8 because there are 8 borders
2424/8 = 303 in
4.- Conclusion
The frame has a width of 303 in
Answer: the width of the frame is 303 inches.
Step-by-step explanation:
Let x represent the width of the frame.
The rectangular painting measures 1212 inches by 1414 inches and contains a frame of uniform width around the four edges. This means that the length of the painting and the frame is 1212 + 2x and the width of the painting and the frame is 1414 + 2x
The formula for determining the perimeter of a rectangle is expressed as
Perimeter = 2(length + width)
The perimeter of the rectangle formed by the painting and its frame is 7676 inches. This means that
2(1212 + 2x + 1414 + 2x) = 7676
2(2626 + 4x) = 7676
Dividing through by 2, it becomes
2626 + 4x = 7676/2 = 3838
4x = 3838 - 2626 = 1212
x = 1212/4 = 303 inches
