Respuesta :
The given question is incomplete. The complete question is as follows.
Brad tries out a weight-loss plan that involves repeatedly lifting a 52.0-kg barbell from the floor over his head to a height of 2.3 m. If he is able to complete three such lifts per minute, how long will it take for him to lose 0.50 kg of fat? "Burning" 1 g of fat supplies 39 kJ to the body; of this, 10% can be used by the muscles to lift the barbell. (Ignore the fat "burned" while he lowers the barbell to the floor.)
Explanation:
For the given situation,
Energy given by his "fat" = work done by the gravity
[tex]0.5 \times 30 \times 10^{3} \times 10^{3} \times \frac{10}{100} = \frac{2.3 \times 52 \times 9.8 \times 3}{60} \times t[/tex]
[tex]15 \times 10^{5} = 58.604 t[/tex]
t = 25595.52 seconds
As there are 3600 seconds present in 1 hour. So, convert 25595.52 seconds into hours as follows.
[tex]\frac{25595.52 seconds}{3600 sec/hr}[/tex]
= 7.10 hours
Thus, we can conclude that it will take 7.10 hours from Brad to lose 0.50 kg of fat.
The time taken for Brad to lose 0.5 kg of fat is : 7.1 hours
Given data:
Mass of barbell = 52 kg
Height reached per lift = 2.3 m
Determine the time taken to burn 0.5 kg of fat
we will apply the formula below
energy given by fat = work done
0.5 * 30 * 10³ * 10³ * 10/100 = ( 2.3 *52 * 9.8 * 3 ) / 60 * t
15 * 10⁵ = 58.604 * t
Therefore t ( time taken to burn 0.5 kg of fat ) = 25595.52 secs
= 7.1 hours
Hence we can conclude that The time taken for Brad to lose 0.5 kg of fat is : 7.1 hours.
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Attached below is the missing part of the question
"Burning" 1 g of fat supplies 39 kJ to the body; of this, 10% can be used by the muscles to lift the barbell. (Ignore the fat "burned" while he lowers the barbell to the floor.)
