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Two flat conductors are placed with their inner faces separated by 17 mm. If the surface charge density on one of the inner faces is 108 pC/m2 and the other inner face -108 pC/m2, what is the magnitude of the electric potential difference between the
two conductors?

Respuesta :

Answer:

Explanation:

electric field between plates

=  surface charge density / ε₀

= 108 x 10⁻¹² / 8.85 x 10⁻¹² (ε₀ = 8.85 x 10⁻¹² )

= 12.20 V/ m

Electric potential diff

= electric field x distance between plates

=  12.20 x 17 x 10⁻³ V

= 0.207 Volt

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