Answer:
Explanation:
To calculate the ATP generated in complete beta-oxidation of stearic acid (an 18-carbon saturated fatty acid ),
number of rounds of beta-oxidation = [tex]n/2 - 1[/tex] ,
where ,n is number of carbon present in fatty acid since , n= 18 in give fatty acid
number of rounds of beta-oxidation = [tex]18/2 - 1 = 8[/tex]
8 rounds of beta-oxidation gives :-
-8[tex]NADH[/tex]
-8[tex]FADH_{2}[/tex]
-8 [tex]Acetyl-CoA[/tex] + [tex]Acetyl-CoA[/tex]
Each rounds of beta oxidation gives 17 ATP , So 8 rounds of beta- oxidation gives 17 × 8 = 136 ATP , while theres's an extra [tex]Acetyl-CoA[/tex] which also undergoes in Krebs cycle along with other 8 [tex]Acetyl-CoA[/tex] , though this extra [tex]Acetyl-CoA[/tex] produce 12 ATP . While 2 molecules of ATP is consumed in activation of fatty acid , So total energy generated in beta-oxidation of stearic acid is 146 .
