Answer:
The value of smaller resistor is 248 Ω.
Explanation:
Voltage divider circuit is used to convert a higher voltage to a smaller voltage with the help of resistors which are connected in parallel.
As shown in the circuit, Vs is the source voltage, R₁ and R₂ are the two resistors and V₀ is the output voltage.
Applying KVL in the circuit, the output voltage is given by :
[tex]V_{0} = \frac{V_{s}R_{2} }{R_{1} + R_{2} }[/tex]
According to the problem, R₂ = 310Ω , V₀ = 5 V and Vs = 9 V. Substitute these values in the above equation.
[tex]5 = \frac{9\times310 }{R_{1} + 310 }[/tex]
[tex]R_{1}+310 = \frac{9\times310}{5}[/tex]
[tex]R_{1} = 558 - 310[/tex]
R₁ = 248Ω
