Respuesta :
Answer:
Option A - 4.91
Step-by-step explanation:
The formula for theoretical standard deviation of uniform distribution is;
σ = √{(b-a)^2}/12
Now from the question, b = 38 minutes and a= 21 minutes
Therefore, σ = √{(38-21)^2}/12
= √{17^2}/12 = √289/12 = 4.907 which is approximately 4.91
The standard deviation of the uniform probability distribution between 21 and 38 minutes is 4.6188.
What is standard deviation of uniform probability distribution?
We know that the formula for the theoretical standard deviation of uniform distribution is given as,
[tex]\sigma = \dfrac{\sqrt{(b-a)^2}}{12}[/tex]
As it is given to us that the uniform probability distribution is between 21 and 38 minutes. Therefore, the value of b is 38 min and the value of a is 21. Now, finding the standard deviation of this distribution,
[tex]\sigma =\sqrt{ \dfrac{(37-21)^2}{12}}\\\\\sigma =\sqrt{ \dfrac{(16)^2}{12}}\\\\\sigma = 4.6188[/tex]
Hence, the standard deviation of the uniform probability distribution between 21 and 38 minutes is 4.6188.
Learn more about Uniform Distribution:
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