Answer : The concentration after 195 seconds is, 1.18 M
Explanation :
The expression used for second order kinetics is:
[tex]kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}[/tex]
where,
k = rate constant = [tex]1.30\times 10^{-3}M^{-1}s^{-1}[/tex]
t = time = 195 s
[tex][A_t][/tex] = final concentration = ?
[tex][A_o][/tex] = initial concentration = 1.68 M
Now put all the given values in the above expression, we get:
[tex]1.30\times 10^{-3}\times 195=\frac{1}{[A_t]}-\frac{1}{1.68}[/tex]
[tex][A_t]=1.18M[/tex]
Therefore, the concentration after 195 seconds is, 1.18 M
