contestada

A simple pendulum consists of a 4.9 kg point mass hanging at the end of a 3.1 m long light string that is connected to a pivot point. Calculate the magnitude of the torque (due to the force of gravity) around this pivot point when the string makes a 3.1 ◦ angle with the vertical. The acceleration of gravity is 9.81 m/s 2 . Answer in units of N · m.

Respuesta :

lublana

Answer:

8.1 N-m

Explanation:

We are given that

Mass=m=4.9 kg

Length=L=3.1 m

[tex]\theta=3.1^{\circ}[/tex]

[tex]g=9.8m/s^2[/tex]

We have to find the magnitude of torque (due to the force of gravity).

We know that

[tex]\tau=mgLsin\theta[/tex]

Using the formula

[tex]\tau=4.9\times 9.8\times 3.1sin3.1^{\circ}[/tex]

[tex]\tau=8.1 N-m[/tex]

Hence, the magnitude of  torque =8.1 N-m

Otras preguntas