Write the slope-intercept form (y=mx+b) of the equation of the line through the given slope.

Answer:
y = [tex]\frac{4}{5}[/tex] x + 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + b ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 5, 0) and (x₂, y₂ ) = (0, 4)
m = [tex]\frac{4-0}{0+5}[/tex] = [tex]\frac{4}{5}[/tex]
Note the line crosses the y- axis at (0, 4) ⇒ b = 4
y = [tex]\frac{4}{5}[/tex] x + 4 ← equation of line
Answer: y = 4x/5 + 4
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis
change in the value of y = y2 - y1
Change in value of x = x2 -x1
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
The line passes through (- 5, 0) and (0, 4),
y2 = 4
y1 = 0
x2 = 0
x1 = - 5
Slope, m = (4 - 0)/(0 - - 5) = 4/5
To determine the intercept, we would substitute x = 0, y = 4 and
m = 4/5 into y = mx + c. It becomes
4 = 4/5 × 0 + c
c = 4
The equation becomes
y = 4x/5 + 4