Answer:
(7, 220) and (-1, -20) (x,y)
Step-by-step explanation:
put value of y in eq 2
30x + 10 = 5x² - 25
5x² - 25 - 30x -10 =0
5x² -30x -35 =0
x² -6x -7 =0 by dividing 5 on both sides
quadratic eq ax²+bx+c=0
a=1, b= -6, c -7
use quadratic formula to find value of x
x= (-b+-√b^2-4ac) / 2a
by putting values of a, b and c
x= (6 ± 8)/2
x= (6 + 8)/2 and x= (6 - 8)/2
x= 14/2=7 x= -2/2= -1
so, x= 7, -1
put values of x in eq 1
for x= 7
y= 30(7) + 10
y= 210 + 10
y= 220
now for x= -1
y= 30(-1) + 10
y= -30 + 10
y= -20
