Respuesta :
Answer: The mass of nitric oxide is 12.72 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For ammonia:
Given mass of ammonia = 8.00 g
Molar mass of ammonia = 17 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of ammonia}=\frac{8.00g}{17g/mol}=0.47mol[/tex]
- For oxygen gas:
Given mass of oxygen gas = 17.0 g
Molar mass of oxygen gas = 32 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of oxygen gas}=\frac{17g}{32g/mol}=0.53mol[/tex]
The given chemical reaction follows:
[tex]4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)[/tex]
By Stoichiometry of the reaction:
5 moles of oxygen gas reacts with 4 moles of ammonia
So, 0.53 moles of oxygen gas will react with = [tex]\frac{4}{5}\times 0.53=0.424mol[/tex] of ammonia
As, given amount of ammonia is more than the required amount. So, it is considered as an excess reagent.
Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
5 moles of oxygen gas produces 4 moles of NO
So, 0.53 moles of oxygen gas will produce = [tex]\frac{4}{5}\times 0.53=0.424moles[/tex] of NO
Now, calculating the mass of NO from equation 1, we get:
Molar mass of NO = 30 g/mol
Moles of NO = 0.424 moles
Putting values in equation 1, we get:
[tex]0.424mol=\frac{\text{Mass of NO}}{30g/mol}\\\\\text{Mass of NO}=(0.424mol\times 30g/mol)=12.72g[/tex]
Hence, the mass of nitric oxide is 12.72 grams
