find the density of seawater at a depth where the pressure is 280 atm if the density at the surface is 1035 kg/m^3. seawater has a bulk modulus of 2.3 x 10^9 N/m^2.

Respuesta :

Explanation:

Formula for Bulk modulus of a material is as follows.

         B = [tex]\frac{pV}{\Delta V}[/tex]      

    (Bulk modulus = pressure × compressibility)

     [tex]\frac{\Delta V}{V} = \frac{p}{B}[/tex]

     [tex]\frac{\Delta V}{V} = 1 - \frac{\rho}{\rho'}[/tex]

Hence,

        [tex]1 - \frac{\rho}{\rho'} = \frac{p}{B}[/tex]

        [tex]1 - \frac{1.03 \times 10^{3}}{\rho'} = \frac{280}{2.3 \times 10^{9}}[/tex]

                [tex]\rho'[/tex] = [tex]1.030 \times 10^{3} kg/m^{3}[/tex]

Therefore, we can conclude that density of seawater at a depth where the pressure is 280 atm is [tex]1.030 \times 10^{3} kg/m^{3}[/tex].