Respuesta :
Answer:
This ball will attain the same range at 60°.
Explanation:
Projectile motion: when an object is thrown in such a way that it form an angle with horizon, the force act on it that is the acceleration due gravity. This type of motion is known as projectile motion.
Range: The horizontal distance is covered by an object.
Range [tex]=\frac{u^2 sin2\theta}{g}[/tex]
u = initial velocity = 40 m/s
θ = 30°
g = gravity =9.8 m/s²
[tex]Range=\frac{40^2\times sin(2\times 30^\circ)}{9.8}[/tex]
[tex]=\frac{800\sqrt{3} }{9.8}[/tex]
Next,
Range [tex]=\frac{800\sqrt{3} }{9.8}[/tex] and u = 40 m/s
[tex]sin2\theta =\frac{Range \times g}{u^2}[/tex]
[tex]\Rightarrow sin2\theta =\frac{\frac{800\sqrt{3} }{9.8} \times 9.8}{40^2}[/tex]
[tex]\Rightarrow sin 2\theta =\frac{\sqrt{3} }{2}[/tex]
[tex]\Rightarrow sin 2\theta = sin 120^\circ[/tex]
[tex]\Rightarrow \theta =120^\circ[/tex]
[tex]\Rightarrow \theta =60^\circ[/tex]
This ball will attain the same range at 60°.
