Answer:
Distance between both the charges will be equal to [tex]r=22.59\times 10^7m[/tex]
Explanation:
We have first charge [tex]q_1=33.5nC=33\times 10^{-9}C[/tex]
And charge [tex]q_2=-50.3nC=-50.3\times 10^{-9}C[/tex]
Force between theses charges are equal to [tex]F=3.30\times 10^{-4}N[/tex]
We have to find the distance between two charges
According to coulomb's law force between two charges is equal to [tex]F=\frac{Kq_1q_2}{r^2}[/tex]
So [tex]3.3\times 10^{-4}=\frac{33.5\times 10^{-9}\times 50.3\times 10^{-9}}{r^2}[/tex][tex]r=22.59\times 10^7m[/tex]
So distance between both the charges will be equal to [tex]r=22.59\times 10^7m[/tex]
