Answer:
Work done on the car will be 548440.9463 J
Explanation:
We have given mass of the car m = 1075 kg
As the car finally stops so final velocity of the car [tex]v_f=0m/sec[/tex]
Initial velocity of car u = 115 km/hr [tex]=115\times \frac{5}{18}=31.943m/sec[/tex]
Work done is equal to change in kinetic energy
So work done [tex]=\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2[/tex]
=[tex]=\frac{1}{2}m(v_f^2-v_i^2)=\frac{1}{2}\times 1075\times (0^2-31.943^2)=-548440.946J[/tex]
As the work done is negative so work is done on the car to stop it .
