"The percent of fat calories that a person consumes each day is normally distributed with a mean of 36 and a standard deviation of 10. Suppose that 25 individuals are randomly chosen. Find the first quartile for the average percent of fat calories."

Respuesta :

Answer:

The first quartile for the average percent of fat calories is 34.65.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], a large sample size can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

In this problem, we have that:

[tex]\mu = 36, \sigma = 10, n = 25, s = \frac{10}{\sqrt{25}} = 2[/tex]

Find the first quartile for the average percent of fat calories.

This is the value of X when Z has a pvalue of 0.25. So X when Z = -0.675.

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central limit theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]-0.675 = \frac{X - 36}{2}[/tex]

[tex]X - 36 = -0.675*2[/tex]

[tex]X = 34.65[/tex]

The first quartile for the average percent of fat calories is 34.65.