Additional Work done to stretch the spring 0.4m is 6.4J
Explanation:
Given -
Work done to stretch a spring, W1 = 8J
Distance , d = 0.5m
Distance2, x = 0.4m
Work done 2, W2 = ?
Using Hooke's law,
Work done = k x
where k is spring constant
For distance 0.5m :
8 J = k X 0.5m
k = 8/0.5 = 16 J/m
For distance 0.4m:
W2 = 16 X 0.4 J
W2 = 6.4J
Additional Work done to stretch the spring 0.4m is 6.4J
