Answer: The jet's speed from A to B would be 5.5 km/hr.
Step-by-step explanation:
Since we have given that
Distance = 2500 meter
Outbound speed be x
Average speed be [tex]\dfrac{100+20}{100}x=\dfrac{120}{100}x=1.2x[/tex]
Time = 9 hours 10 minutes = [tex]9\dfrac{10}{60}=9\dfrac{1}{6}=\dfrac{55}{6}[/tex]
According to question, it becomes,
[tex]\dfrac{2.5}{x}+\dfrac{2.5}{1.2x}=\dfrac{55}{6}\\\\\dfrac{1.2x+x}{1.2x^2}=\dfrac{55}{6\times 2.5}\\\\\dfrac{2.2x}{1.2x^2}=\dfrac{11}{3}\\\\\dfrac{2.2}{1.2x}=\dfrac{11}{3}\\\\2.2\times 3=1.2x\\\\6.6=1.2x\\\\\dfrac{6.6}{1.2}=x\\\\x=5.5\ km/hr[/tex]
Hence, the jet's speed from A to B would be 5.5 km/hr.
