In a shipment of 71 vials, only 13 do not have hairline cracks. If you randomly select 2 vials from the shipment, what is the probability that none of the 2 vials have hairline cracks.

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Answer:

0.0313

Step-by-step explanation:

Given that in the shipment of 71 vials, only 13 do not have hairline cracks

Probability of not having a hairline cracks = [tex]\frac{13}{71}[/tex]

If you randomly select 2 vials from the shipment

(Probability of not having a hairline cracks)' = [tex]\frac{13-1}{71-1}[/tex] = [tex]\frac{12}{70}[/tex]

what is the probability that none of the 2 vials have hairline cracks.

i.e [tex](\frac{13}{71}) * (\frac{12}{70})[/tex]

= 0.183 × 0.171

= 0.0313

Hence, the probability that none of the 2 vials have hairline cracks = 0.0313