Respuesta :
Answer:
Therefore the magnitude of required electric force is 292.864×10⁻⁵ N.
Explanation:
The number of proton of iron is 26.
[tex]1.6\times 10^{-19}[/tex] C is the charge of each proton.
Total charge of 26 proton is =(26×1.6×10⁻¹⁹) C
=41.6×10⁻¹⁹ C
The charge of innermost electron is = - [tex]1.6\times 10^{-19}[/tex] C
Coulomb's Law:
The attraction or repulsion force of two charges is
- directly proportional to the product of the charges.
- inversely proportion to the square of distance
Let [tex]q_1 \ and \ q_2[/tex] be two positive charge and the distance between the charges be r
Then F∝[tex]q_1 q_2[/tex]
and [tex]F \propto \frac{1}{r^2}[/tex]
Therefore,
[tex]F=\frac{kq_1q_2}{r^2}[/tex]
Here
[tex]q_1[/tex]= - [tex]1.6\times 10^{-19}[/tex]C and [tex]q_2[/tex] =41.6×10⁻¹⁹ C
r = 1.5× 10⁻¹² m
K= 9.9× 10⁹C²N⁻¹m⁻²
Therefore
[tex]F=\frac{9.9 \times 10^9\times (-1.6\times 10^{-19})\times 41.6\times 10^{-19}}{(1.5\times 10^{-12})^2}[/tex] N
= -292.864×10⁻⁵ N
The mins sign shows the direction of the force.
Magnitude of electric force is only the numerical value of the force.
Therefore the magnitude of required electric force is 292.864×10⁻⁵ N.
