Answer: The dimensions of the garden would be 18 feet and 24 feet.
Step-by-step explanation:
Let the width of garden be 'x'.
Let the length of garden be [tex]'x+6'[/tex]
Since there is 3 foot wide walkway surrounds the outside the garden.
Area of walkway = 288 square feet
So, According to question, it becomes,
[tex]2z(x+y+2z)\\\\288=2\times 3(x+x+6+2\times 3)\\\\288=6(2x+6+6)\\\\288=6(2x+12)\\\\\dfrac{288}{6}=2x+12\\\\48=2x+12\\\\48-12=2x\\\\36=2x\\\\x=\dfrac{36}{2}\\\\x=18[/tex]
Width = 18+6 =24 feet
Hence, the dimensions of the garden would be 18 feet and 24 feet.
