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26-02-2020
Physics

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What is the magnitude of the electric field strength between them, if the potential 7.95 cm from the zero volt plate (and 2.05 cm from the other) is 413 V?

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Supabrain Supabrain

27-02-2020

Answer:

ΔVab = Ed

ΔVab = Va-Vb = Va-V0 = Va

E = Va/ d

= 413V / 0.0795 m

= 5194.97 V/M

Explanation:

the potential difference between two uniform plates is calculated by the formula of electric field.

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