Answer:
[tex]8.71*10^{-15}[/tex]
Explanation:
The rest energy is the energy associated with the base ball at zero velocity which is expressed as
[tex]Rest energy=mc^{2}\\[/tex]
Note: the speed C is the speed of light which is expressed as 3*10^8
while the kinetic energy is the energy associated with the ball during its motion and is expressed as
[tex]Kinetic energy=1/2mv^{2}[/tex]
the ratio can be expressed as
[tex]\frac{Kinetic Energy}{Rest Energy}=\frac{\frac{1}{2}mv^{2} }{mc^{2}}\\since V=39.6m/s\\C=3*10^{8}m/s\\\frac{Kinetic Energy}{Rest Energy}=\frac{\frac{1}{2}39.6^{2} }{(3*10^8)^{2}} \\\frac{Kinetic Energy}{Rest Energy}=\frac{784.08}{9*10^{16}} \\\frac{Kinetic Energy}{Rest Energy}=8.71*10^{-15}[/tex]
