Answer: The value of [tex]\lim_{x \to 5} P(x)[/tex] is 39.
Step-by-step explanation:
Since we have given that
[tex]P(x)=\dfrac{90+60x}{x+5}[/tex]
where x be the number of days of on the job training.
We need to find the [tex]\lim_{x \to 5} P(x)[/tex]
So, it becomes,
[tex]\lim_{x \to 5} \dfrac{90+60x}{x+5}\\\\ =\dfrac{90+60\times 5}{5+5}\\\\=\dfrac{90+300}{10}\\\\=\dfrac{390}{10}\\\\=39[/tex]
Hence, the value of [tex]\lim_{x \to 5} P(x)[/tex] is 39.