Answer:
The speed of the stone just before it hits the ground is 18.54 m/s
Explanation:
Given that,
Initial speed of the stone, u = 8 m/s
The stone is thrown downward from a height of 14 m
We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :
[tex]v^2-u^2=2ah[/tex]
v is the speed of the stone just before it hits the ground
[tex]v^2=2ah+u^2[/tex]
[tex]v^2=2\times 10\times 14+(8)^2[/tex]
v = 18.54 m/s
So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.
