A current of 12.5 mA is maintained in a single circular loop with a circumference of 2.55 m. A magnetic field of 0.750 T is directed parallel to the plane of the loop. What is the magnitude of the torque exerted by the magnetic field on the loop

Respuesta :

Answer:

Torque [tex]= 4.856 * 10^{-3}[/tex] Nm

Explanation:

Torque can be calculated by using below given relation

[tex]T= BIA[/tex] ---------- Equation (1)

Where T is the torque in Nm

B is the magnetic field in Tesla

I is the current in Ampere

and A is the area in square meter

Since the current is flowing in circular loop, its area will be equal to [tex]A = \pi r^2[/tex]

Circumference [tex]= 2 \pi r[/tex]

[tex]2.55 = 2 * 3.14 * r\\r = \frac{2.55}{2*3.14} \\r = 0.406[/tex]

Substituting the value of r in the formula of area we get -

[tex]A = 3.14 * (0.406)^2\\A = 0.518[/tex]

Substituting all the values in equation 1

[tex]T= 0.75 * 12.5 * 10^{-3} * 0.518 \\T = 4.856 * 10^{-3}[/tex]