Answer:
[tex]P(X\geq 5)=0.69[/tex]
Step-by-step explanation:
We need to find the probability that the mechanic will service or more cars.
It's a simpler one given that we have the probabilities of servicing 4 or less cars.
P(at least 5 cars) is given by subtracting the probabilities of servicing both 3 and 4 cars.
[tex]P(X\geq 5)=1-p(x=4)-p(x=3)\\P(X\geq5)=1-0.12-0.19\\P(X\geq5)=1-0.31\\=0.69[/tex]
