Answer:
Q = A ⊕ B = (A AND B) + ( not(A) AND not(B) )
Explanation:
AND gates : only output 1 when both inputs are 1
OR gate: only output 1 when either or both of the inputs are 1
NOT gates: takes only one input ad output the opposite of the input
The required circuit should takes two inputs and outputs a 1 if and only if the two inputs are the same signal.
The two possible scenarios : both input are 1's or 0's
Q = A ⊕ B = (A AND B) + ( not(A) AND not(B) )
A B not(A) not(B) A AND B not(A) AND not(B) Q
0 0 1 1 0 1 1
0 1 1 0 0 0 0
1 0 0 1 0 0 0
1 1 0 0 1 0 1
