Answer: The increase in temperature is 10°C
Explanation:
To calculate the change in temperature, we use the equation:
[tex]q=mc\Delta T[/tex]
where,
q = heat absorbed = 200 kCal = 200,000 Cal (Conversion factor: 1 kCal = 1000 Cal)
m = mass of water = 20 kg = 20000 g (Conversion factor: 1 kg = 1000 g)
c = specific heat capacity of water = 1 Cal/g.°C
[tex]\Delta T[/tex] = change in temperature = ?
Putting values in above equation, we get:
[tex]200,000Cal=20,000g\times 1J/g.^oC\times \Delta T\\\\\Delta T=\frac{200,000Cal}{20,000g\times 1Cal/g^oC}=10^oC[/tex]
Hence, the increase in temperature is 10°C
