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As an audio CD plays, the frequency at which the disk spins changes.

At 210 rpm, the speed of a point on the outside edge of the disk is 1.3 m/s.

At 420 rpm, the speed of a point on the outside edge is ___ m/s.

Respuesta :

Answer:

The velocity is 2.5997 m/s.  

Explanation:

The given condition :-

1) N = 210 rpm

speed ( v ) = 1.3 m/s.

We know that ,

v = r ω

where r = radius of disk.

ω = angular velocity.

But ω = [tex]\frac{2*\pi*N }{60}[/tex]

[tex]v = \frac{r* 2*\pi*210 }{60}[/tex]

[tex]1.3 = \frac{r*2*\pi*210 }{60}[/tex]

r = 0.059144 m

2) N = 420 rpm

[tex]v = \frac{r* 2*\pi*N }{60}[/tex] [tex]= \frac{0.059144*2*3.14*420}{60}[/tex]    

v = 2.5997 m/s.  

So we get the velocity v = 2.5997 m/s.