Answer:
5 seconds
Step-by-step explanation:
The height is modeled by the function [tex]h(t)=80t-16t^2[/tex] :
#Factor out t:
[tex]h(t)=80t-16t^2\\\\\#Equate \ to \ zero\\0=80t-16t^2\\\\t(80-16t)=0\\\\t=0\\\\80-16t=0\\\\80=16t\\\\t=5[/tex]
Hence, the ball is thrown from the ground, goes up and comes back down and hits the ground 5 seconds later, t = 5