Answer: [tex]log_3(c)-log_3(9)[/tex]
Step-by-step explanation:
By definition, equivalent expressions have the same value, but they look different.
For this exercise you need to remember one of the properties for logarithms. This is:
[tex]log_b(\frac{a}{c})=log_b(a)-log_b(c)[/tex]
You know that the expression given in the exercise is the following:
[tex]log_3(\frac{c}{9})[/tex]
As you can notice, "c" is divided by 9.
Based on the property shown at the beginning of this explanation, you can write this logarithm as a subtraction of two logarithms (You must remember that the base must be the same, as you can observe in the property given above).
Therefore, keeping that property on mind, you get the following expression which is equivalent to [tex]log_3(\frac{c}{9})[/tex]:
[tex]log_3(c)-log_3(9)[/tex]
