Respuesta :
Answer:
1. $225.238905
2. 16 minutes or 0.27 hours
Step-by-step explanation:
1.
1000w costs $50.05309 hence 1 w will cost $0.05005309
Each electric heater consumers 1500 W so for three, the total heat consumption will be 1500w*3=4500 W
Cost for the three heaters will be 4500*$0.05005309=$225.238905
Therefore, in 1 day, Laura will spend $225.238905 on heating alone
2.
1 kwh costs $50.05309 hence for 0.075 kwh it will sots 0.075*$50.05309=$3.75398175 Therefore for $1 you will spend [tex]\frac {1}{3.75398175}=0.26638382032624426051085623951155 hours[/tex]
This is approximately 16 mins
Answer:
- $5.73 per day
- 251.1 hours
Step-by-step explanation:
Given
the cost of electricity is $0.05309 for each kilowatt hour used.
Find
- The one-day cost to use three 1500-watt electric heater
- The number of hours for a 75 W light bulb to use $1 of electricity
Solution
1. The cost is the product of the number of kW, the number of hours, and the cost per kWh:
(1.5 kW/heater)(3 heaters)(24 hours)($0.05309/kWh)
= (108 kWh)($0.05309/kWh)
= $5.73
It costs Laura $5.73 per day to heat her house.
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2. We want to find the number of hours (H) to run a .075 kW bulb for a cost of $1.
$1 = (.075 kW)(H)($0.05309)
H = 1/(0.05309·0.075) = 1/0.00398175 ≈251.1 . . . hours
A 75 W bulb can run about 251.1 hours on $1 worth of electricity.