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The basketballs Noah packed had two different prices. Of the total number of basketballs sold, 60% had a price that was $21 more than the price of the remaining basketballs. The total amount of the store’s sales for all the basketballs was $8,967. What was the price for one of the more expensive basketballs?

Respuesta :

Answer:

$(8967/n + 8.4)

Step-by-step explanation:

0.4nx + 0.6n(x+21) = 8967

nx + 12.6n = 8967

x = 8967/n - 12.6

x+21 = 8967/n + 8.4

Where n is the no. of balls

Example: if total balls were 300

n = 300

More expensive one would cost:

8967/300 + 8.4 = $38.29

The cost of the more expensive basketball is required.

Price of more expensive basketball is $45.

The total number of basketballs is 245

60% of the basketballs = [tex]0.6\times 245=147[/tex]

40% of the basketballs = [tex]0.4\times 245=98[/tex]

Cost of total basketballs is $8967

Let cost of lower price basketball be [tex]x[/tex]

[tex]98x+147(21+x)=8967\\\Rightarrow 98x+3087+147x=8967\\\Rightarrow x=\dfrac{8967-3087}{147+98}\\\Rightarrow x=24[/tex]

Price of more expensive basketball is [tex]21+24=\$45[/tex]

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